Java 8 – How to sort a Map 修改教程

sorting sorting

Few Java 8 Stream examples to sort a Map

1. Sort by Key

SortByKeyExample.java

package com.mkyong.test;

import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.Map;

public class SortByKeyExample {

    public static void main(String[] argv) {

        Map<String, Integer> unsortMap = new HashMap<>();
        unsortMap.put("z", 10);
        unsortMap.put("b", 5);
        unsortMap.put("a", 6);
        unsortMap.put("c", 20);
        unsortMap.put("d", 1);
        unsortMap.put("e", 7);
        unsortMap.put("y", 8);
        unsortMap.put("n", 99);
        unsortMap.put("j", 50);
        unsortMap.put("m", 2);
        unsortMap.put("f", 9);

        System.out.println("Original...");
        System.out.println(unsortMap);

        Map<String, Integer> result = new LinkedHashMap<>();

        //sort by key, a,b,c..., and put it into the "result" map 
        unsortMap.entrySet().stream()
                .sorted(Map.Entry.<String, Integer>comparingByKey())
                .forEachOrdered(x -> result.put(x.getKey(), x.getValue()));

        System.out.println("Sorted...");
        System.out.println(result);

    }

}

Output

Original...
{a=6, b=5, c=20, d=1, e=7, f=9, y=8, z=10, j=50, m=2, n=99}

Sorted...
{a=6, b=5, c=20, d=1, e=7, f=9, j=50, m=2, n=99, y=8, z=10}

2. Sort by Value

SortByValueExample.java

package com.mkyong.test;

import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.Map;

public class SortByValueExample {

    public static void main(String[] argv) {

        Map<String, Integer> unsortMap = new HashMap<>();
        unsortMap.put("z", 10);
        unsortMap.put("b", 5);
        unsortMap.put("a", 6);
        unsortMap.put("c", 20);
        unsortMap.put("d", 1);
        unsortMap.put("e", 7);
        unsortMap.put("y", 8);
        unsortMap.put("n", 99);
        unsortMap.put("j", 50);
        unsortMap.put("m", 2);
        unsortMap.put("f", 9);

        System.out.println("Original...");
        System.out.println(unsortMap);

        Map<String, Integer> result = new LinkedHashMap<>();

        //sort by value, and reserve, 10,9,8,7,6...
        unsortMap.entrySet().stream()
                .sorted(Map.Entry.<String, Integer>comparingByValue().reversed())
                .forEachOrdered(x -> result.put(x.getKey(), x.getValue()));

        System.out.println("Sorted...");
        System.out.println(result);

    }

}

Output

Original...
{a=6, b=5, c=20, d=1, e=7, f=9, y=8, z=10, j=50, m=2, n=99}

Sorted...
{n=99, j=50, c=20, z=10, f=9, y=8, e=7, a=6, b=5, m=2, d=1}

3. Generic Example

Create a generic method to sort a Map.

SortByGenericExample.java

package com.mkyong.test;

import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.Map;
import java.util.stream.Stream;

public class SortByGenericExample {

    public static void main(String[] argv) {

        Map<String, Integer> unsortMap = new HashMap<>();
        unsortMap.put("z", 10);
        unsortMap.put("b", 5);
        unsortMap.put("a", 6);
        unsortMap.put("c", 20);
        unsortMap.put("d", 1);
        unsortMap.put("e", 7);
        unsortMap.put("y", 8);
        unsortMap.put("n", 99);
        unsortMap.put("j", 50);
        unsortMap.put("m", 2);
        unsortMap.put("f", 9);

        System.out.println("Original...");
        System.out.println(unsortMap);

        System.out.println("Sort By Key...");
        Map<String, Integer> resultKey = compareByKey(unsortMap);
        System.out.println(resultKey);

        System.out.println("Sort By Value...");
        Map<String, Integer> resultValue = compareByValue(unsortMap);
        System.out.println(resultValue);
    }

    //Reference from java.util.Map source code, try dig inside, many generic examples.
    public static <K, V extends Comparable<? super V>> Map<K, V> compareByValue(Map<K, V> map) {

        Map<K, V> result = new LinkedHashMap<>();

        Stream<Map.Entry<K, V>> mapInStream = map.entrySet().stream();

        mapInStream.sorted(Map.Entry.comparingByValue())
                .forEachOrdered(x -> result.put(x.getKey(), x.getValue()));

        return result;

    }

    public static <K extends Comparable<? super K>, V> Map<K, V> compareByKey(Map<K, V> map) {

        Map<K, V> result = new LinkedHashMap<>();
        Stream<Map.Entry<K, V>> mapInStream = map.entrySet().stream();

        mapInStream.sorted(Map.Entry.comparingByKey())
                .forEachOrdered(x -> result.put(x.getKey(), x.getValue()));

        return result;

    }

}

Output

Original...
{a=6, b=5, c=20, d=1, e=7, f=9, y=8, z=10, j=50, m=2, n=99}

Sort By Key...
{a=6, b=5, c=20, d=1, e=7, f=9, j=50, m=2, n=99, y=8, z=10}

Sort By Value...
{d=1, m=2, b=5, a=6, e=7, y=8, f=9, z=10, c=20, j=50, n=99}

Note
Not using Java 8? Try this classic way to sort a Map in Java.

References

  1. How to sort a Map in Java
  2. More Fun with Wildcards
  3. Collections.sort() signature
  4. Difference between and in Java

如果觉得JSRUN的教程对您有用,请随意打赏。您的支持将鼓励JSRUN继续提供更好的服务

捐助JSRUN
JSRUN前端教程共编系统是国内最先开创的教程维护系统, 所有工程师都可以参与共同维护的本前端教程,让知识的积累变得统一完整、自成体系。 希望广大工程师能一起参与进共编,让零散在世界各处的知识点找到组织、找到家。
X
支付宝
9.99
请使用支付宝扫码支付, 有效时间 5分0秒
超过有效时间后请立即停止支付。
支付故障请联系QQ:565830900
因10.00元通道已占用,系统建议您支付9.99元
正在生成二维码, 此过程可能需要15秒钟
谢谢支持,我一定会更加努力的